The gambler

A gambler shows you a box with 5 white and 2 black marbles in it. All the marbles are identical except for their color. He invites you to draw without replacement 3 marbles from the box while you are blindfolded, and you lose if you draw a black marble.

If you lose $10 for losing the game, how much should you get paid for winning it for your mathematical expectation to be zero (i.e. to make it a fair game)?


The answer is 25.

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1 solution

Denton Young
Jun 3, 2015

First we have to calculate your probability of winning. Your chances of drawing 3 consecutive white marbles without replacement are (5/7) * (4/6) * (3/5), which simplifies to 2/7.

So if you play 7 games, on average you will lose 5, which means you will pay out 5 * 10 = $50. To make the game fair, you need to bring in $50 during your two wins, so you need to be paid (50/2) = $25 per win.

Could you please explain how do we solve this using hypergeometric distribution ?

S B - 3 years, 1 month ago

It makes sense, but If I use the formula of Hypergeometric distribution I have that Pr(X=3) = f(3; 8, 5, 3) = [C(5, 3)*C(3, 0)]/C(8, 3) = 5/28 = 0,1786. Maybe I need to add other probabilities (with value equal to 3/28) and I can achieve 2/7.

Erico Farias - 1 year, 6 months ago

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