The Greek Marketplace

Algebra Level pending

One day, a Greek entered a marketplace. He saw three apples, two oranges, and four bananas. Each apple costed one more than the difference of the 3 3 bananas and 2 2 oranges. ( 3 3 bananas cost more than 2 2 oranges). The Greek bought 1 1 apple, 2 2 oranges and 4 4 bananas. He paid 22 22 dollars. Each orange costed $ 2.75 \$2.75 . What was the price of the apple?

$4.50 $4.00 $5.75 $2.75 $3.50

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2 solutions

Let a a be the cost of the one apple, b b be the cost of one banana and c c be the cost of one orange.

From the second sentence in the problem, the equation is

a = 3 b 2 c + 1 a=3b-2c+1 , however, c = 2.75 c=2.75 , therefore a = 3 b 2 ( 2.75 ) + 1 = 3 b 4.5 a=3b-2(2.75)+1=3b-4.5 ( 1 ) \color{#D61F06}(1)

From the third and fourth sentences in the problem, the equation is

a + 2 c + 4 b = 22 a+2c+4b=22 , however, c = 2.75 c=2.75 , therefore a + 2 ( 2.75 ) + 4 b = 22 a+2(2.75)+4b=22 \color{#3D99F6}\large \implies a + 4 b = 16.5 a+4b=16.5 ( 2 ) \color{#D61F06}(2)

Substitute ( 1 ) \color{#D61F06}(1) in ( 2 ) \color{#D61F06}(2) . we have

3 b 4.5 + 4 b = 16.5 3b-4.5+4b=16.5 \color{#3D99F6}\large \implies 7 b = 21 7b=21 \implies b = 3 b=3

It follows that,

a = 3 ( 3 ) 4.5 = a=3(3)-4.5= 4.5 \color{#D61F06}\large \boxed{4.5}

Micah Gadbois
Jul 17, 2017
  1. We assign variables. "A" stands for apple, "C" stands for orange, and "B" stands for banana.
  2. The first requirement: A = 1+3B-2C
  3. Thus, 1+3B-2C+2C+4B = 22
  4. 7B = 21
  5. B = 3
  6. Since we know C = 2.75, 2C = 5.5
  7. 4B+2C = 12 + 5.5 = 17.5
  8. 22 - 17.5 = 4.5
  9. A = 4.5

Assigning "O" for orange is not a good idea, since "O" looks like "0" (zero). For example in the second line of your solution, "2O" means two oranges, but it looks like "20" (twenty). That's why I used the variable c c to represent orange in my solution for clarity.

A Former Brilliant Member - 3 years, 10 months ago

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