One day, a Greek entered a marketplace. He saw three apples, two oranges, and four bananas. Each apple costed one more than the difference of the bananas and oranges. ( bananas cost more than oranges). The Greek bought apple, oranges and bananas. He paid dollars. Each orange costed . What was the price of the apple?
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Let a be the cost of the one apple, b be the cost of one banana and c be the cost of one orange.
From the second sentence in the problem, the equation is
a = 3 b − 2 c + 1 , however, c = 2 . 7 5 , therefore a = 3 b − 2 ( 2 . 7 5 ) + 1 = 3 b − 4 . 5 ( 1 )
From the third and fourth sentences in the problem, the equation is
a + 2 c + 4 b = 2 2 , however, c = 2 . 7 5 , therefore a + 2 ( 2 . 7 5 ) + 4 b = 2 2 ⟹ a + 4 b = 1 6 . 5 ( 2 )
Substitute ( 1 ) in ( 2 ) . we have
3 b − 4 . 5 + 4 b = 1 6 . 5 ⟹ 7 b = 2 1 ⟹ b = 3
It follows that,
a = 3 ( 3 ) − 4 . 5 = 4 . 5