The Higgs mechanism

As we saw previously, a wave solution is possible - the dispersion relation for the wave simply becomes

E 2 = p 2 c c + m 2 c 4 + g 0 2 c 2 E^2 = p^2 c^c + m^2 c^4 + g_0 \hbar^2 c^2 .

Now comes the fun part - why bother having a mass at all? If the mass and g 0 g_0 are both constants, then anything I can do with a mass term I can do with g 0 g_0 . This is the essence of the Higgs mechanism: I can generate a mass for particles by coupling the particle to this extra "Higgs field" and setting the empty space value of the field to some constant g 0 g_0 . The different masses for photons, electrons, muons, etc. are determined by how strongly each particle/field couples to the Higgs field, which allows each species of particle to essentially feel the effect of a non-zero g 0 g_0 differently and hence have different masses.

How does one generate a non-zero g 0 g_0 ? This is done via the dynamics of the Higgs field itself. The Higgs field interacts with itself, but how it interacts is dependent on who you talk to (it's a matter of debate). In one common example, the Higgs field satisfies an equation of the form

( 1 c 2 2 t 2 2 x 2 A + B g 2 ( t , x ) ) g ( t , x ) = 0 (\frac{1}{c^2} \frac {\partial^2}{\partial t^2} - \frac {\partial^2}{\partial x^2} - A + B g^2(t,x)) g(t,x)=0

where the last two terms are the result of the Higgs field interacting with itself. The lowest energy solution to this equation is when the Higgs field is a constant g 0 g_0 everywhere, and as we know, nature likes to settle into states of lowest energy (hence this constant value is the natural value we expect the Higgs field to be in in our universe). If the Higgs field is such a g 0 g_0 everywhere, what is g 0 g_0 in terms of A and B?

A / B \sqrt{A/B} A/B ( A / B ) 2 (A/B)^2 0

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Okay! First of all, wow! Higgs Field ROCKS!!! :P

Now, since g ( t , x ) g(t,x) is a constant g o { g }_{ o } , hence it's partial derivative, with respect to time and it's position, is going to give a zero. So, we are left with the last two terms of the differential equation.

Given that g o { g }_{ o } is a non zero constant, i.e. the Higgs field, MUST interact with itself, the former part of the equation must be zero, that is,

A + B g 2 ( t , x ) = 0 g ( t , x ) = A B \quad \quad -A+Bg^{ 2 }\left( t,x \right)=0\\ \Rightarrow g\left( t,x \right)=\sqrt { \frac { A }{ B } }

Hope, i got this write! :D Cheers!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...