The Hyperloop: speed

Since the Hyperloop travels $560 \frac{km}{\frac{1}{2} hour},$ it must travel at a rate of $\frac{560}{\frac{1}{2}} \frac{km}{hour}.$ This means that it travels $1,120,000 \frac{meters}{3600 \ seconds},$ due to the fact that $1 km = 1,000$ meters and $1$ hour = $3,600$ seconds. Thus, dividing out, we get a rate of $\frac{\frac{2800}{9} \ meters}{second}.$

v=560000/30/60=311.1 m/s

The speed of the hyperloop in $kmh^{-1}$ is:

$\frac{\text{distance}}{\text{time}} = \frac{560}{\frac{1}{2}} = 1120 kmh^{-1}$ .

To convert speed in $kmh^{-1}$ to $ms^{-1}$ , we multiply by a factor of $\frac{5}{18}$ .

$\Rightarrow$ Speed of the hyperloop in $ms^{-1} = 1120 \times \frac{5}{18} = \boxed{311.1111\dots}$ .

S=D/T = 560×10^3/30×60 {convert distance km to m and time 1/2 an hour which means 30mins to secs.} = 311.11 m/s