% of the earth's mass, and the speed of the asteroid just before the collision is times faster than that of the earth.)
In classical mechanics, linear momentum is the product of an object's mass and velocity. In a closed system (one that does not exchange any matter with the outside world and is not acted on by any outside forces) the total momentum is constant. If a huge asteroid impacts the earth in the same direction as the earth's movement, how will it change the speed of the earth? (Assume that the impact of the asteroid is a perfectly inelastic collision, the mass of the asteroid is
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The mass of the asteroid is 1 A , and its speed is 1 0 E (using the made-up units A and E referring to the mass of the asteroid and the speed of the Earth). In this unit scheme, the mass of the Earth is 1 0 0 A and its speed is 1 E .
Since momentum is found through the formula p = m v , the momentum of the asteroid is 1 0 A E and the momentum of the Earth is 1 0 0 A E . The total momentum after the collision, then, is equal to the sum of the momentums of the Earth and the asteroid, or 1 1 0 A E .
Now that we have the momentum, all that's left is the find the velocity. Rearranging p = m v gives us v = m p . The total mass after the collision is 1 0 1 A (100 from the Earth and 1 from the asteroid), meaning that the ending velocity is 1 0 1 A 1 1 0 A E ≈ 1 . 0 8 9 E . This is 8 . 9 % greater than the starting velocity of the Earth.