If is a polynomial of degree , and if is a function of degree , the degree of )) can be expressed in the form , where , , and are coprime, positive integers. Find .
Note : The notation means that is iterated , or repeatedly carried out, times. For example, means .
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Instead of letting P = a 1 x 2 + b 1 x + c 1 and f ( x ) = a 2 x 4 + b 2 x 3 + c 2 x 2 + d x + e , we could let P = x 2 and f ( x ) = x 4 , since we only want to find the degree after they are manipulated.
Now,
f ( x ) = x 4
f ( 2 ) ( x ) = ( x 4 ) 4 = x 4 2
f ( 3 ) ( x ) = ( x 4 2 ) 4 = x 4 3
.
.
f ( n ) ( x ) = x 4 n , and this is what we will use to solve the problem.
Here is the one we have to solve:
f ( 1 9 ) ( P ⋅ f ( 1 9 ) ( P ))
= f ( 1 9 ) ( x 2 ⋅ f ( 1 9 ) ( x 2 ))
= f ( 1 9 ) ( x 2 ⋅ ( x 2 ) ( 4 1 9 ) )
= f ( 1 9 ) ( x 2 ⋅ ( x 2 ) ( 2 3 8 ) )
= f ( 1 9 ) ( x 2 ⋅ ( x 2 3 9 ) )
= f ( 1 9 ) ( x 2 + 2 3 9 )
= ( x 2 + 2 3 9 ) 4 1 9
= ( x 2 + 2 3 9 ) 2 3 8
= x 2 3 9 + 2 7 7
Thus, a = 2 , b = 3 9 , c = 7 7 , and a + b + c = 2 + 3 9 + 7 7 = 1 1 8