The jogging fly

Just like every other morning, two friends living 10 km 10\text{ km} apart start jogging towards each other. At the same time, a fly on the head of one of the joggers also starts flying towards the other, back and forth, until the friends meet.

What is the distance flown by the fly in kilometres if both of the friends jog at a velocity of 5 km / h \SI[per-mode=symbol]{5}{\kilo\meter\per\hour} and the fly flies at the velocity of 10 km / h ? \SI[per-mode=symbol]{10}{\kilo\meter\per\hour}?


The answer is 10.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Djordje Veljkovic
Mar 11, 2017

In a fascinating book, T i m e t r a v e l a n d O t h e r M a t h B e w i l d e r m e n t s Time\space travel\space and\space Other\space Math\space Bewilderments , Martin Gardner tells the story of a Hungarian mathematician, John von Neumann who was asked to solve this problem at a celebration. Neumann gave the answer almost instantly disappointing the asker. The answer he gave was very simple. Given the velocities of the friends, and the distance between them, it's easy to say that it'll take one hour for them to meet. Given that the fly crosses 10 k m h \frac{km}{h} , it's easy to say that the distance the fly flew is 10 km

The answer he gave was actually that he "simply" summed the geometric series. That's what made the anecdote so funny. The questioner thought he knew the trick, when he actually didn't. John von Neumann was the sort of man who could simply do inhuman things like that.

Steven Chase - 4 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...