The first original geometry problem in 2015!

Geometry Level 5

It is given a triangle A B C ABC with A C B = 112 ° \measuredangle ACB=112° and A C = B C AC=BC and a point M M in the interior, for which M B A = 26 ° \measuredangle MBA=26° and M A B = 30 ° \measuredangle MAB=30° What is the measure in (degrees) of M C B ? \measuredangle MCB?

NOTE: This problem is original!


The answer is 86.

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1 solution

Maria Kozlowska
Jun 30, 2015

By Trigonometric Form of Ceva's Theorem:

sin ( 30 ) sin ( 4 ) sin ( 112 x ) sin ( x ) sin ( 8 ) sin ( 26 ) = 1 x = 86 \frac {\sin (30) }{\sin (4)} \frac {\sin (112-x)}{\sin (x)} \frac {\sin (8)}{\sin (26)} = 1 \Rightarrow x = 86 M C B = 86 \Rightarrow \angle MCB = 86

Solution 2

Triangle ABC can be constructed inside an equilateral triangle ABC' with point M as a vertex of a smaller equilateral triangle positioned at the center of the triangle ABC'. The angle measures match the requirements stated in the problem and the unknown angle can be easily computed.

Hi, can you please show how this equation is solved?

Thanos Petropoulos - 1 year, 3 months ago

@Thanos Petropoulos -- Is there any pure geometry solution possible?

Ajit Athle - 4 months, 1 week ago

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