A stair case contains three steps having height 10 cm each. if each are 20 cm wide then the minimum horizontal velocity of a ball moving off the upper mark plane so as to hit the lowest plane directly is(in m/s)
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To hit directly the lowest plane the ball has to cross the point B. From A to B, the ball has to travel to horizontal distance equal 40cm =40m and vertical distance of 20cm=0.2m.
Let the time taken to reach point be t.u=0 m/s h=0.2m from the equation, h=ut+1/2gt²
we get 0.2=0+1/2 x9.8 t² t²=0.4/9.8 t²=0.04 t=0.2 Let v be the horizontal velocity of ball than the horizontal distance travelled by the ball=0.2v in order to clear the point B it must be equal to 0.40. 2v=0.4 v=2m/s ∴So minimum velocity required to to hit the lowest floor is 2 m/s