A person being chased by a lion is running in a straight line
towards his car at a constant speed of
4
m
s
−
1
.The car is at a
distance of
d
metres away from the person. The lion is
2
6
m
behind the person and running at a constant speed of
6
ms
−
1
. The person reaches the car safely . What is the maximum
possible value of
d
in metres ?
Note: Suppose that the person takes no time to sit in the car.
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Thanks ! Edited.
I solved in the same way! Nice!
Nice solution ,+1!
nice one (+1) !
Man's speed = 4 m s − 1 , Lion's speed = 6 m s − 1
Relative speed = 6 − 4 = 2 m s − 1
Which means that lion is gaining 2 meters every second. Following this, after 13 seconds he will be eaten alive. He better reach his car in 13 seconds.
Maximum distance the man can run in 13 seconds= 1 3 s e c o n d s × 4 m s − 1 = 5 2
Another interesting approach, +1!
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Thanks a lot ;).
a better solution..+1!
Consider a time 't' after which the man covers the distance 'd' ; Now since the speed of the man is 4m/s & that of lion is 6m\s , Therefore we can write ⟶
d = 4 t .......... ( 1 ) &
2 6 + d = 6 t ........ ( 2 )
Solving these two equations, we get t = 1 3 , Putting this value of t in the second equation we get our answer as d = 5 2 m .
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To find the maximum distance/displacement, Time taken by the Lion and the person to reach the car must be equal t Lion = t Person ⟹ 4 d = 6 d + 2 6 3 d = 5 2 + 2 d ⟹ d = 5 2 m
NOTE: Please Mention that we to submit our answer in meters