The Marksman

In a shooting match, 8 clay targets are arranged in two hanging columns of three each and one column of two. A marksman must break the targets in the following way:

  • The marksman first chooses a column.
  • The marksman must break the lowest unbroken target in that column.

Suppose the rules are followed and the marksman never misses. How many ways can the marksman shoot the targets?

360 560 480 720 400 520

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1 solution

Shaoping Ge
Sep 1, 2017

Once the marksman picks a target, he has to shoot in one place. He can shoot at two of the columns three times and shoot at one of the columns two times, in any order. Therefore he can shoot in 8 ! 3 ! 2 ! 2 ! \frac{8!}{3! * 2! * 2!} = 560 ways.

This is an AIME problem

Aditya Kumar - 3 years, 4 months ago

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