The maximum a!!

Algebra Level 5

Find the maximum value of a a , if

( x 2 + x + 2 ) 2 ( a 3 ) ( x 2 + x + 2 ) ( x 2 + x + 1 ) + ( a 4 ) ( x 2 + x + 1 ) 2 = 0 (x^2+x+2)^2-(a-3)(x^2+x+2)(x^2+x+1)+(a-4)(x^2+x+1)^2=0

has at least one real root.


The answer is 6.333.

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1 solution

Magomed Dunkaev
Jun 2, 2015

Let's say x^2 +x +1 = y, so x^2 +x+2 = y+1 ( I just did it in order to make the expression look easier). After replacing, we have :

(y+1)^2 - y(y+1)(a-3) + y^2(a-4) = 0

After simplifying, what we get is :

5y - ya + 1 = 0

Now, let's return our big expressions:

5(x^2 +x +1) - a(x^2 + x +1) + 1 = 0

You finally should get quadratic equation:

(5-a)x^2 + x(5-a) + (6-a) = 0

Now, according to conditions, the equation has to have at least one root. So, the D value ( b^2 - 4ac) has to be greater or equal than 0 ( if it is equal, we have one root, if it is greater, we have 2 roots):

D = (5-a)^2 - 4(6-a)(5-a) >= 0

This leads us to a quadratic inequality :

-3a^2 +34a - 95 >= 0

After solving inequality, you get [5 ; 6.333]. So, the maximum value of a is 6.333.

What I did is simple replacing. It is a very powerful technique.

SOLVED

I also did the same wa but thats a long method. Is there Any shortcut or any other method .

Akshay Sharma - 5 years, 6 months ago

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