Find the maximum value of , if
has at least one real root.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let's say x^2 +x +1 = y, so x^2 +x+2 = y+1 ( I just did it in order to make the expression look easier). After replacing, we have :
(y+1)^2 - y(y+1)(a-3) + y^2(a-4) = 0
After simplifying, what we get is :
5y - ya + 1 = 0
Now, let's return our big expressions:
5(x^2 +x +1) - a(x^2 + x +1) + 1 = 0
You finally should get quadratic equation:
(5-a)x^2 + x(5-a) + (6-a) = 0
Now, according to conditions, the equation has to have at least one root. So, the D value ( b^2 - 4ac) has to be greater or equal than 0 ( if it is equal, we have one root, if it is greater, we have 2 roots):
D = (5-a)^2 - 4(6-a)(5-a) >= 0
This leads us to a quadratic inequality :
-3a^2 +34a - 95 >= 0
After solving inequality, you get [5 ; 6.333]. So, the maximum value of a is 6.333.
What I did is simple replacing. It is a very powerful technique.
SOLVED