If one machine pumps a pool in four hours and a second machine pumps the same pool in three hours, how fast would a third machine have to be for all three machines to finish pumping the pool in one hour? Answer in pools per hour round to the nearest hundredths.
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r a t e w o r k d o n e = t i m e The sum of all rates must equal 1 hour 4 1 + 3 1 + x = 1 1 2 7 + x = 1 x = 1 − 1 2 7 = 1 2 5 therefore the missing rate is 1 2 5 h o u r p o o l s rounded to the nearest 0.01=0.42