The More, The Mightier

Calculus Level 4

Lanchester's Square Law can be used to roughly describe the way in which two opposing military forces change over time during battle. Suppose the number of troops in "Force A" is A A , and the number of troops in "Force B" is B B .

The rates of change in troop strength (numbers of troops) over time are given by: d A d t = B \dfrac{dA}{dt} = -B and d B d t = A \dfrac{dB}{dt} = -A .

Suppose that A = 2 A=2 and B = 1 B=1 at time ( t = 0 ) (t=0) . What is the value of A A at the moment in time at which A = 100 B A=100B ?

Give your answer to 3 decimal places.

Details and Assumptions :

  • Assume that A A and B B can vary continuously, and that they are multiples of some standard measure.

  • Evidently, the larger force has a distinct advantage if all else is equal.


For those who are interested, you can read up Lanchester's Law here .


The answer is 1.732.

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1 solution

Steven Chase
Aug 12, 2016

Relevant wiki: First Order Differential Equations - Problem Solving

Interestingly, the answer is approximately s q r t ( 3 ) sqrt(3) but not exactly.

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