A motorist travels from Hyderabad to Mumbai at a speed of 40 kmph and returns back with a speed of 60 kmph . What is is his average speed (in kmph)?
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As the distance covered in both the cases is same , the average speed will be equal to ( let u be the initial speed and v be the final speed) 2uv/u+v. In the given case , Average Speed =2.40.60/40+60 = 48 kmph .