Find the smallest integer greater than 1000 and divisible by 37.
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Why did you divide and multiply 37 to get the answer?
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When we divide 1000 by 37 it gives a reminder of 1 which is 36 less than the 37 thats why we just have to add 36 into 1000
3 7 1 0 0 0 × 3 7 = 1 0 0 0 , but 1000 is not divisible by 37. This is because 3 7 1 0 0 0 = 2 7 . 0 2 7 0 2 7 0 3 is not an integer. The ceiling function ⌈ x ⌉ returns the least integer ≥ x . Therefore ⌈ 3 7 1 0 0 0 ⌉ = 2 8 and 2 8 × 3 7 = 1 0 3 6 gives the least multiple of 3 7 ( > 1 0 0 0 ) . Similarly, the floor function, ⌊ 3 7 1 0 0 0 ⌋ = 2 7 gives the greatest integer ≤ 3 7 1 0 0 0 and 2 7 × 3 7 = 9 9 9 is the greatest multiple of 3 7 ( > 1 0 0 0 ) .
Thanks for the tricks, sir.
1 0 0 0 ≡ 1 ( m o d 3 7 ) ⇒ 1 0 0 0 + 3 6 ≡ 1 + 3 6 ≡ 3 7 ≡ 0 ( m o d 3 7 ) ⇒ 1 0 3 6 ≡ 0 ( m o d 3 7 )
Hence , 1 0 3 6 is the required integer. :)
1000/37 = 27.027
37 * 0.027 = 1
1000 - 1 = 999
999/37 = 27
999 + 37 =1036
1036/37 = 28
1036 (Ans.)
Even I found the answer by this method. Easiest to think of :)
3700- 37x100 1850-37x50 925-37x26 925plus37 plus 37 -999 Hence add 37 to arrive at 1036 the smallest integer above 1000
Divide 1000 by 37 .Reminder is 1.So the next Number more than 1000 divisible by 37 is 1036
37 × 3 = 111
37 × 27 = 999 < 1000
37 × 28 = 1036
or
999 + 37 = 1036
1 0 0 0 = 3 7 × 2 7 + 1
then the smallest integer n divisible by 3 7 is n = 3 7 ∗ 2 8 = 1 0 3 6 .
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The smallest integer, n > 1 0 0 0 , divisible by 37 is:
n = ⌈ 3 7 1 0 0 0 ⌉ × 3 7 = 2 8 × 3 7 = 1 0 3 6