Two consecutive odd numbers are such that three times the first is 5 more than twice the second. What are those two odd numbers?
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Let the first number be x. Since the numbers are consecutive, therefore the second number must be x+2.
It is given that... 3 times the first number = 5 + 2 times the second number
3 * x = 2 * (x+2) + 5
3x = 2x + 4 + 5
3x - 2x = 4 + 5
x = 9
Therefore numbers must be X=9, x+2=11