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Chemistry Level 3

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of Carbon Dioxide. The Hydrocarbon contains x x gram atoms of Carbon and y y gram atoms of Hydrogen. x y \frac{x}{y} =


The answer is 0.875.

Abhiram Rao by Abhiram Rao , 18, India

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1 solution

Ashish Menon
May 1, 2016

The equation is C x H y + ( x + y 4 ) O 2 → x C O 2 + y 2 H 2 O C_xH_y + (x + \dfrac{y}{4})O_2 \rightarrow xCO_2 + \dfrac{y}{2}H_2O
1 mole of water = 18g. So, 0.72 g = 0.04 moles. So, y 2 = 0.4 ; y = 0.8 \dfrac{y}{2} = 0.4 ; y = 0.8
1 mole of carbon dioxide = 44g. So, 3.08g of carbon dioxide = 0.7 moles.
∴ x y = 0.7 0.8 = 0.875 \therefore \dfrac{x}{y} = \dfrac{0.7}{0.8} = \boxed{0.875}


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