The Relation

Classical Mechanics Level 2

A body starts from rest and acquires a velocity $V$ in time $T$ . The work done on the body in time t is proportional to:

\dfrac{Vt}T

\dfrac{V^2\times t}{T^2}

\dfrac{V^2\times t^2}{T}

\dfrac{V^2\times t^2}{T^2}

1 solution

Syed Amaan Haider
Feb 10, 2016

acceleration of body, a=V/T velocity acquired in time t, v=at=V.t/T kinetic energy is directly prop. to V^2 hence, work done ids d.p. to V^2.t^2/T^2