The RESULTANT.....

Algebra Level 2

Tushar wrote a two digit number. He added 5 to the tens digit and subtracted 3 from the units digit of the number. The resulting number is twice the original number. Find the original number ?


The answer is 47.

Tushar Malik by Tushar Malik , 20, India

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1 solution

Be 10 a + b 10a+b the number.

After the modification in the number, we have:

10 ( a + 5 ) + b − 3 = 10 a + 50 + b − 3 = 10 a + b + 47 10(a+5)+b-3=10a+50+b-3=10a+b+47

The number modified is twice the original number or:

20 a + 2 b = 10 a + b + 47 20a+2b=10a+b+47

Simplifying:

20 a + 2 b = 10 a + b + 47 20a+2b=10a+b+47

20 a + 2 b − 10 a − b = + 47 20a+2b-10a-b=+47

10 a + b = 47 10a+b=47

So, the original number is 47 \boxed { 47 }

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