The Right Time

Geometry Level 2

During each hour, the clock hands will always make a right angle twice as shown above.

Will the time gap between these 2 instances be constant for every hour?

No Yes Not enough information

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The minute hand will move 360 6 = 6 \dfrac{360}{6}=6 degrees clockwise every minute while the hour hand will move 30 60 = 0.5 \dfrac{30}{60} = 0.5 degree, for each hour only accounts for 360 12 = 30 \dfrac{360}{12} = 30 degrees. Thus, each minute the angle between these hands will decrease by 6 0.5 = 5.5 6 - 0.5 = 5.5 degrees.

Once the hands make the first right angle, they will continue to move closer to each other until they are superimposed (making 0 0 degrees) and will start to form increasing angle of constant rate to eventually make a second right angle.

In other words, the time gap between these right angles equal 90 + 90 5.5 = 360 11 33 \dfrac{90+90}{5.5} = \dfrac{360}{11} \approx 33 minutes for every hour.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...