The length of one of the legs of a right angled triangle exceeds the length of the other leg by 10 cm but is smaller than that of the hypotenuse by 10 cm. Find the length of the hypotenuse.
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Let,
Given side=x cm
Therefore,
.'.Hypo. = x+10 cm
.'.III Side = x-10 cm
Accor. to Pythagoras' Thm.,
Hypo^2 = Side I^2 = Side II^2
.'.(x+10)^2 = x^2 + (x-10)^2
.'.,As we Know;
x^2 + 20x + 100 = x^2 + x^2 - 20x + 100
.'. 0 = 2x^2 - x^2 - 20x - 20x +100 -100
.'. 0 = x^2 - 40x
.'. 40x = x^2
.'. 40x/x = x
.'. 40 = x
.'.x = 40 cm
.'.Hypo. = x + 10 cm
.'.Hypo. = 40 cm + 10 cm
.'.Hypo. = 50 cm