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Compute (1+1)+(1-1)+(1x1)+(1÷1)+(1^1)+(1^1/1)+(0^1)+(1^0)+(1^x), where x is the smallest number that has more than 500 factors.

9 5 6 8 7

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1 solution

(1+1)+(1-1)+(1x1)+(1÷1)+(1^1)+(1^1/1)+(0^1)+(1^0)+(1^x) has 9 addends, and we solve then here:

1+1=2

1-1=0

1x1=1

1÷1=1

1^1=1

1^1/1=1^1=1

1^0=1

0^1=0

1^x always equals 1, so 1^x=1

So the answer is 2+0+1+1+1+1+0+1+1=8

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