Compute (1+1)+(1-1)+(1x1)+(1÷1)+(1^1)+(1^1/1)+(0^1)+(1^0)+(1^x), where x is the smallest number that has more than 500 factors.
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(1+1)+(1-1)+(1x1)+(1÷1)+(1^1)+(1^1/1)+(0^1)+(1^0)+(1^x) has 9 addends, and we solve then here:
1+1=2
1-1=0
1x1=1
1÷1=1
1^1=1
1^1/1=1^1=1
1^0=1
0^1=0
1^x always equals 1, so 1^x=1
So the answer is 2+0+1+1+1+1+0+1+1=8