An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length (In m)for the runway?
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vi = 0 m/s
vf = 65 m/s
a = 3 m/s2
Find:
d = ?? vf2 = vi2 + 2 a d (65 m/s)2 = (0 m/s)2 + 2 (3 m/s2) d
4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d
(4225 m2/s2)/(6 m/s2) = d
d = 704 m