The Same situation prevails.........Round round round round.......
Classical Mechanics
Level
3
The distance traveled by a particle thrown upwards in the last second of its ascent in SI units obviously is ..... Ain;t the question too short,......... yes friends may be i can get a long answer ........
The answer is 4.9.
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1 solution
You see It's a simple question, The following facts will conclude you your answer
The time of ascent is equal to the time of descent
The velocity of particle in ascent and decent are equal at each point of its motion
And the most interesting one, The distance traveled by the particle in the first second of its ascent is equal to the distance traveled by it in the last second of its descent .......and so the distance traveled by it in the last second of its ascent is equal to the distance traveled by it in the first second of its descent
Required answer is
S = 2 g t 2 S = 2 9 . 8 X 1 2 S = 4 . 9