The Secants....

Geometry Level 2

Two secants are drawn to a circle from the same external point. The segments of one secant that lie inside and outside the circle are 9 cm and 3 cm, respectively. The segment of the other secant that lies inside the circle is twice its segment lying outside the circle. What is the length (in cm) of the second secant?

6\sqrt{3} 5\sqrt{2} 8\sqrt{3} 7\sqrt{2}

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1 solution

We have A B = 3 AB=3 , B D = 9 BD=9 , A C = x AC=x and C E = 2 x CE=2x . Then, by Power of a Point we have: A B ( A B + B D ) = A C ( A C + C E ) AB(AB+BD)=AC(AC+CE) . That is: 3 ( 3 + 9 ) = x ( x + 2 x ) 3(3+9)=x(x+2x) . Solving that, we obtain:

36 = 3 x 2 x = 2 3 36=3x^2 \Longrightarrow x=2\sqrt{3}

Finally, the length of A E AE is 3 x 3x , so A E = 6 3 AE=6\sqrt{3} .

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