Two secants are drawn to a circle from the same external point. The segments of one secant that lie inside and outside the circle are 9 cm and 3 cm, respectively. The segment of the other secant that lies inside the circle is twice its segment lying outside the circle. What is the length (in cm) of the second secant?
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We have A B = 3 , B D = 9 , A C = x and C E = 2 x . Then, by Power of a Point we have: A B ( A B + B D ) = A C ( A C + C E ) . That is: 3 ( 3 + 9 ) = x ( x + 2 x ) . Solving that, we obtain:
3 6 = 3 x 2 ⟹ x = 2 3
Finally, the length of A E is 3 x , so A E = 6 3 .