The second Ace

You have seven cards in your hand in a random order, and two are Aces.

You flip them over one at a time until you have flipped over both Aces.

The expected number of flips is a b \frac{a}{b} where a a and b b are coprime positive integers.

What is a + b a+b ?


Image credit: s.hswstatic.com


The answer is 19.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Geoff Pilling
Nov 1, 2018

There are ( 7 2 ) = 21 \binom{7}{2} = 21 possibilities for the positions of the Aces.

  • 6 of them result in the second Ace being in the 7th position.
  • 5 of them result in the second Ace being in the 6th position.
  • 4 of them result in the second Ace being in the 5th position.
  • 3 of them result in the second Ace being in the 4th position.
  • 2 of them result in the second Ace being in the 3th position.
  • 1 of them results in the second Ace being in the 2nd position.

So,

E = 1 2 + 2 3 + 3 4 + 4 5 + 5 6 + 6 7 21 = 16 3 E = \dfrac{1\cdot2 +2\cdot3 +3\cdot4 +4\cdot5 +5\cdot6 +6\cdot7}{21} = \dfrac{16}{3}

16 + 3 = 19 16 + 3 = \boxed{19}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...