The Shape-Shifting Triangle

Geometry Level 3

If the angle A of triangle ABC is doubled and the lengths of AB and AC are kept the same, the area of the triangle remains the same. Find angle A (in degrees).

This sum is from the 1994 AMTI Screening Test


The answer is 60.

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2 solutions

Take the triangle ABC.

By sine law,

Area of triangle ABC = (1/2) × \times b × \times c × \times sin \sin A = (1/2) × \times b × \times c × \times sin \sin 2A = (1/2) × \times b × \times c × \times 2 × \times sin \sin A × \times cos \cos A

Therefore, cos \cos A = 1/2

Therefore, angle A = 60

Agnes Fung
May 19, 2014

Area of triangle = 1 2 × \frac{1}{2} \times a b sin \sin c

c c in this case = A \angle A

1 2 × \frac{1}{2} \times a b sin A = 1 2 × \sin \angle A = \frac{1}{2} \times a b sin 2 A \sin \angle 2A

sin A = sin 2 A \sin A = \sin 2A

A = 60 \angle A = \boxed{60}

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