The Shooting Game

$\{x+y=100, ~x-y=30\} ~~~~\Longrightarrow ~~x=\fbox{65}$

30+[(100-30)/2]=65

Let $T$ denotes that he hit the target and $M$ denotes that he miss the target.

Since he played $100$ times, we have

$T+M=100$ $\color{#D61F06}(1)$

Since he earned $\$30$ , we have

$1(T)-1(M)=30$ $\implies$ $T-M=30$ $\color{#D61F06}(2)$

Adding $\color{#D61F06}(1)$ and $\color{#D61F06}(2)$ , we get

$2T=130$

$\boxed{T=65}$

Let x be the number of hits.

1x - 1 ( 100 - x ) = 30

x - 100 + x = 30

2x = 130

x = 65

Number of times hit = h and number of times missed = m total h + m = 100 and h – m = 30 adding 2h = 130

h = 65

The answer is 65 he hit the target 65 times and got 65 Taka then He missed the target 35 times.. (65+35)times = 100 times

when he missed he lost 35 Taka thus he earned (65 - 35)Taka = 30 Taka :) :)

He has to win 65 games and miss 25 hits, so he paid 25 Taka and earned 65. Which is 65-25=30

total shooting is 100,he has hit totally 65 targets and missed 35 35-35+30=100

x+y=100 x-y=30 solve simultaneously x=65

let,he hits the target x times so,if we make a equation with given information,it will be x-(100-x)=30 or,2x=130 or,x=65

give to equation: let x = hit, y=missed hit = taka x + y = 100 (eq1), x-y = 30(eq2)... (x+y = 100) +( x-y = 30)... 2x = 130... x = 65

100-30 = 70 so 70/2 = 35 he misses 35 times. and hits target 30+35=65 times.

let no of times hit be x no of times missed=100-x so 30=x-100-x implies x=130/2=65

Its simply mind calculating ques sorry cant explain it in wrds...

Let the times he hit the target be X and the times he failed it be Y. x - y = 30 x = 30 + y

x + y = 100 by substitution of x 30 + y + y = 100 2y + 30 = 100 2y = 100 -30 2y = 70 y = 35

x = 100 - 35 = 65

if sumon has shooted 65 times out of 100 and missed 35 times so she has to return 35 Taka out of 65. remaining will be 30.

solution; i just made a simple analysis...since the shooter earned 30 taka after playing 100 times...so 100-30=70....from these remaining 70 games a 50% miss and 50% hits brings to conclusion that he did not earn taka fom these 70 games which satisfy the fact that he only earned 30 taka.Then it follows that from the 70 games he hit 35 plus 30,which resulted to 65 in all.;)

70+30=100,70-30=40,60+40=100,60-40=20, we have to get difference 30,so,they should exist between them so,they are 65,35,/65+35=100,65-35=30.

as he hits 100 times and he hits the target for sure 30 times and the rest is ( 100-30) or 70. And when he hits he'll get 1 tk and when he doesn't he pays 1 tk. so devide 70 by 2 and more 35 times he has hit the targets and 35 times he has missed the target. So he hit the target 65 times.

X=hit Y=miss X+y=100 X-y=30 2x=130 X=65 Y=35

50 hits and 50 misses results in earning of 0 takka, 60 hits and 40 miss fires can earn 20 takka, 65 hits and 35 miss fires will give 30 takka. :)

let x = # of hits; y = # of misses; x + y = 100; //equation 1 x - y = 30; //equation 2

therefore, x = 65

Let no. of target he hit =x , no. of target he missed = y , total no. of hits=100, therefore x+y=100---------------- 1 Taka earned by hitting target= x, taka loosed by missing a hit= y so, x-y= 30-------------------------------2 adding 1 and 2 we get (x+y) +(x-y) =100+30 2x=130 So, x= 65

65 is correct answer

let he hit the target x times then he didnt hit the target {100-x} times ATQ 1.x -{100-x}=30 solving above equation x=65

let the no. of hits be x. then no. of misses will be 100-x. hence x-(100-x)=30 x=65

x = No. of times target is hit y = No. of misses

x - y = 30 x + y = 100

Solve. x = 65

65 time he hit the target

let x =number of times Sumon hit the target,y=no of time he misses the target then x-y=30 and x+y=100 by solving these two ,you are able to get 65 as the answer.:)

let m=no. of times he hit & n=no. of times he missed; m+n=100 & m-n=30; therefore m=65.

Let no. of times hit be x, and no. of times missed be y. Total no. of trials, x + y = 100. Total no. of taka earned, x (1) + y (-1) = 30. Hence, x = 65 and y = 35.

If he hits 65 times and missed the target 35 times so 65-35=30, so earned 30 taka.

since he has earned 30 taka,all the remaining money he has earned and the money he spend are cancelled. It means in the remaining 70 attempts the perfect hits and fails are same so that the total money he spend and earned are cancelled together. It means he has 35 perfect hits in those 70 attempts. Totally there are (30 + 35 =)65 perfect attempts.And hence total money he earned is 30 taka.

Total Shoot =65

Earning Point =30

So miss =35

Ans: 65-30 =30

As she has earned 30 takka after total 100 tries. total tries are x + y =100 ( x number of times she missed, y number of times she hot the target) when she misses she pays 1 takka means -x takkas she has to pay when she hit the target she is payed 1 takka means y takkas she has earned so, -x + y = 30 solving both equation so 2y = 130 ----> y = 65 (time hit) so x = 35 (times miss)

Let the number of wrong shots is X , then the number of right shots is X+30 , then: X+X+30=100 2X=70 X=35 The right shots = 100 - 35 = 65

let target hit =x; let target missed =y; as per as problem x + y=100; and x-y=30; adding both equation we get x=65;

He receives 1 for each hit and -1 for each miss - the misses + hits add up to 100 - So misses = (100-x) where x is a hit. [1 x] - [1 (100-x)] = 30

x-(100-x) = 30

x-100+x = 30

2x-100 = 30

2x = 130

x = 65 (hits)

Verify by 65-(100-65) = 30

65-35 = 30

VERIFIED

Solving the equations is one way but graphing the two equations is an alternate and honestly as a method has more real world applications as quite often a 'close' but not intersecting occurrence is a viable option. The two equations are x + Y =100 and x-y = 30

30-30+5-5+30=30 so he hit the target 65 times and miss it 35times

Let the no. of questions answered correctly be x. Then,(100-x)questions are answered correctly=1(x) => x. therefore, x-(100-x)=30. 2x=130. x=65.

Let the number of times target hit be x,then x-(100-x)=30 -> x=65

Sumon Shoot 65 times and missed 35 times. thus, he got 65 takas but he has to lose 35 takas because of missing. therefore, 65-35= 30

Let the number of times he hit the target be 'x'. So the number of times he didn't hit the target would be '100-x' (because he played 100 times - given in question). For every correct hit, he earns one Taka and loses one Taka for every miss. So 1 x + (-1) (100-x) = 30 Solving it further, we get 2x - 100 = 30 -> x=65 Therefore, he hit the target 65 times.

X - (100 - X) = 30

==> X = 65 ;

Lets, x is number of hit and y is number of miss

x+y=100, x-y=30, (x+y)+(x-y)=100+30, 2x=130, x=65 , y=35, ... SO x=65 ans

x-y = 30 x+y=100 Solve using Algebra

Let H represent "Hits" and M, "Misses." Attempts: H + M = 100 (i) Money reward (in Taka): H - M = 30 (ii) Algebraic manipulation (i) +(ii) gives: 2H = 130 Making H = 65. Thus (for completeness) from any of the aforementioned equations, M = 35.

after total 100 tries he have 30 taka so its mean there is the trade off between 70 taka for managing 70 taka he have to win 35 times and loose 35 times by which the left 30 wins can give him 30 taka so totally he have to win 30+35 =65 times to get 30 taka

Answer
= 30 + (100 – 30) / 2
= 30 + 35
= 65

Let A be the no. times he hit the target and B be the no. Of times he miss it.now we know, A+B=100 and A-B=30 (GIVEN ) HENCE BY SOVING These EQ. We get 65

$30 + \frac{100-30}{2} = 30 + \frac{70}{2} = 30 + 35 = \boxed{65}$

Answer is 65.

65+35 = 100, 65 - 35 =30

If he has 30 takas after shooting hundred times then at 70 shoots he should have 0 takas . Therefore out of the seventy he hits 35 and misses 35. So, 30 + 35=65

mine was wild guess

No algebra is required.

Let, he hits 'x' times correctly.

Therefore he misses '100 - x' times.

Now, he gains 1 point for every correct hit and losses 1 point for every miss.

Therefore, Points he gains = 1 * x = x

and, Points he loses = 1 * (100-x) = 100-x

Now, finally he has 30 points. Means, after adding total gain and loss he has 30 points.

Therefore, x - (100-x) = 30 ...('x' is taken positive because these are the points he gains while '100-x' is taken negative because these are the points he losses)

=> x-100+x = 30

=> x+x = 30+100

=>2x = 130

or x = 65.

simple first 100-35=65 thats answer

100 times play 65 times hit and 35 times missed than 65-35=30 ans is 65

MANUALLY BY BACK CALCULATION.......

if he hits 65 targets and remaining 35 targets is miss ,then 65-35=30 taka

The number of he hits the target are x (x is positive integer)

The number of he hits misses the target are 100 – x

Therefore, we have equation x – (100 – x) = 30 <=> x = 65

The number of he hits the target are 65

100 shooting = 30 correct (as earned 30 Tk) + positive 35 shooting & - 35 negative shooting. To earn the 30 Tk. have to score 30+35 = 65 correct shooting.

He earned 30 taka after playing 100 times, which mean 30 aims are wins, From 70 (100-30) he has no gain no loss. so divide by 70/2 =35, it`s mean 35 hits are win and 35 are loss. so 30+35=65 which is total hits win.

he made 30 profit , played 100 games which means the other 70 had to even out to 0 so 70/2 = 35 that's 35 games lost and 35 games won meaning he didn't gain or loose any money so he had to win the other 30 games to make the 30 profit in total that would be 35+30=65 games won

Let x be number of times he hits ; and y is the the number of time he missed Because for each hits he gets 1Taka and missed lose 1Taka So : x - y = 30 As we know x + y = 100 => x + y = x + x - 30 = 2x - 30 = 100 => x = (100 + 30)/2 So x = 65

as he if shoot 30 & unshoots 30 there has completed 60 shoots, in remaining 40 he shoots -35 & UN shoots 5. thus totally he shoots 65. wins 30 taka.

X = Hit Y = Not Hit 1st Equations X + y = 100 2nd Equations X - Y = 30 => X = 30 + Y Substitute X=30 + Y to 1st equations 30+Y + Y = 100 ----------> 30 + 2Y = 100 2Y = 70 Y = 35

Substitue Y = 35 to 1st equations X + Y = 100 X + 35 = 100 X = 100 - 35 X = 65

So Hit = 65

if hits 35 and he miss the 35 35 target - 35 misses = 0 total playing 70 times remaining 30 time he targeted so totally torget the 35+30=65 times.

30 times is the sure hit. 70 is 50% hit because he balanced the wins and losses and earned zero.

30 + 70(0.5) = 65

if he hits 65 targets and miss 35 targets, then 65-35=30

65 hit 35 misses (Earned: 65-35=30 out of 100 times he played)

let x be the no of times he wins ,then 100-x is the no of tyms he loses.so 1^100+(-1^(100-x))=30.finally u get x=65

Let X be no. of hits and Y be no. of misses. He played 100 times so X+Y=100. And He got 30 taka means 1 x-1 y=30. Adding both equations 2X =130 hence X = 65 = No. of times he hit the target

LET X = NO OF WINS AND Y=NO OF DEFEATS. THIS GIVES RISE TO ALGEBRAIC SIMULTANEOUS EQUATIONS AS BELOW X + Y = 100 AND X - Y = 30. ADDING TWO EQUATIONS WE GET, 2X = 130 YIELDING X= 65

Let X be no of hits and Y be the no of miss

According to the problem X + Y = 100 (as he plays for 100 times)

&

X 1 - Y 1 = 30 (as he earns 30 takka) therefore 2X = 130 therefore he hits the target 65 times

>>Let $h$ be the number of hits and $m$ the number of misses.

>> We know that he played 100 times, thus $h + m = 100$ .

>> Well, the exercise tell us that he earned $30$ Taka, so, $h - m = 30$ .

>> Solving $h + m = 100$ and $h - m = 30$ , we have $\boxed{65}$ number of hits.

n-n+x=30 n=30 x=30 so n=35 so total 30+35=65

The total no of time played is 100. Let us take x as no: of times he had hit the target and y to be no: of times he misses the target Therefore x + y = 100(1) now x has the value +1 as it hits target and y to be -1 Since total Taka he earned is 30 .when considering that 1 for x and -1 for it adds to 30 Therefore x 1 + y -1 =30 (2) By addition solving method, (1) = (2), x + y =100 x - y = 30

 2x = 130 
   x =  65

You can check it ! THanx !

let no of times he get his target be x and no of times he lose his target be y. now, x+y=100 =>x=100-y...........(1) x-y=30 =>x=30+y...............(2) from (1) and (2) 100-y=30+y =>100-30= 2y =.y=35 therefore,no of times he get his target=100-y=100-35=65

he wins game 65 times(earn 65 takas) times but loses the game 35times(pay 35 takas). 65-35=30.