A smart coconut seller has three bags full of coconuts with him. Each bag has 30 coconuts. The man has to pass through 30 gates and on each gate he has to give the guards as many coconuts as he has bags. At the end how many coconuts will be left with him?
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There are 90 coconut so for passing first 10 gates he has to give 30 coconuts as he has 3 bags. Now only two bags remain. So for next 10 he gives 20 coconuts @ 2 each. Now the remaining coconuts are 40 i.e. 30 in bag and 10 in 2nd bag. Therefore for first 5 guards, he gives 10 coconuts @ 2 each. Now only one bag remains. Thus next 5 guards get one coconut each.
Therefore total coconuts remaining= 90-(30+20+10+5)=25