THE SPEED....

Algebra Level 2

A body travels from point A to B with speed 30 km. Then returns to the starting point A with speed 20 km.Find the avg. speed of the body?


The answer is 24.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

14 solutions

Rab Gani
Mar 9, 2014

The distance travel from A to B is 30x, where x is the time. The time taken from B to A is 30x/20= 1.5x.The average speed is 60x/2,5x = 24km/h.

I like your approach to the problem!! I solved it too, but in a lengthy way.

Prasun Biswas - 7 years, 2 months ago

Log in to reply

You always do that in a lengthy way.......

Sahba Hasan - 7 years, 2 months ago

Log in to reply

Hmm....is that so ?? :D

Prasun Biswas - 7 years, 2 months ago

nice method....the longer one is kinda more obvious and uninteresting, yours is good

Krishna Ramesh - 7 years, 1 month ago

The best way to do is to use the formula 2xy/x+y.

Anuj Shikarkhane - 6 years, 11 months ago
Khandakar Rahman
Mar 19, 2014

If the distance is 'x'

Average Speed will be, Av. Speed (Km/H) = [x/30 + x/20] / 2 = [50x/600] / 2 = x/24
Av Speed = 24 Km/H (where, x = 1, 2, 3, ....)

Majharul Haque
Mar 20, 2014

Avg speed=2xy/(x+y)

Vishnudatt Gupta
May 13, 2014

Say, a car travels at S1 mph on a trip and at S2 mph on return trip. What is its average speed for the entire trip?

Solution:

* Don't fall in the trap of just averaging the 2 speeds. Overall average speed is not (S1+S2)/2.


Total average speed is simply = Total distance/Total time

Lets say,

D = distance travelled by the car in EACH direction

t1 = time spent on onward trip

t2 = time spent on return trip

Thus, the total distance travelled by the car = D+D= 2D

And, by the formula, Speed = Distance/Time

S1 = D/t1 => t1 = D/S1

S2 = D/t2 => t2 = D/S2

Total average speed = Total Distance/Total time = 2D/(t1+t2) = 2D/(D/S1+D/S2) =

2S1*S2/(S1+S2)

so put values we get 20*30/50=24

Krishna Garg
Apr 30, 2014

Here the distance between point A & B are not given,so taking travelling points suppose 30 KM, going from A to B will take 2 hr,while coming back from B to A will take 1 hr 30 mts. So travelling 60 Km takes 150 mts. Avg speed is thus 60/150 =24 Km/hr Ans

K.K.GARG,india

Toufique Imam
Mar 31, 2014

The distance travel from A to B is 30x, where x is the time. The time taken from B to A is 30x/20= 1.5x. The average speed is 60x/2,5x = 24km/h.

Chinmay Patil
Mar 30, 2014

1/avg velocity = 1/N (1/V1 +1/V2)

Where N= one time journey (1/2), V1 = first velocity (30), V2=second velocity (20)

Dominic D
Mar 27, 2014

If the distance from A to B is 60 km, then it took him 2 hours to get to point B and 3 hours to get back. So if he traveled 120 km in 5 hours, his average speed is 24 km/h.

Kathy Pham
Mar 25, 2014

S: distance from A to B (2S)

T: time from A to B + time from B to A

v1 = 30km/h; v2 = 20km/h

T= t1 + t2 = S/v1 + S/V2 = S/30 + S/20 = S/12

Average speed: V = S/T = 2S/T =2S x 12/S = 24km/h

Dipesh Kumbhkar
Mar 25, 2014

speed=distance/time let x be distance total distance=2x total time=x/20 +x/30 avg speed =2* 20 * 30/50=24

Chandan Singh
Mar 21, 2014

This is good question. Shortcut is good for this like == Average speed= 2 (S1 S2)/(S1+S2) Where S1 and S2 are speeds of the body. Answer= 2 30 20/(30+20)= 24 km

Sunil Pradhan
Mar 20, 2014

avg speed = (2 × 20 × 30)/(20 + 30) = 24 shortcut formula = 2(s1 × s2)/(s1 + s2) wher s1 and s2 are speeds.

Nilesh Shelar
Mar 19, 2014

AVD SPEED=(2 * S1 * S2) / (S1 + S2)

=(2 * 30 * 20) / ( 30 + 20)

=24

B Sathyanarayana
Mar 18, 2014

average speed - 2 * u * v/(u+v)

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...