The squares of doom.

Geometry Level pending

Below shows 2 identical right angled triangles with a square in each of them. If the square inscribed in the first triangle is 50cm^2, find the length of the second square in the second triangle.

5 2 c m 5√2 cm 6 2 3 c m 6 \frac{2}{3} cm 50 c m 50 cm 49 4 9 c m 49 \frac{4}{9}cm

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1 solution

Anbuselvi Me
Jun 3, 2021

The squares are not the same and I am asking for a side. The figures should be divided like this. The first triangle is divided into 8 parts and the other into 9 parts. So the first square is 4/8 of the figure and the second square is 4/9 of the figure. Since the triangles are the same we should find them first. 4/8 is 50cm^2 so multiply that by 2 and get 8/8 is 100cm^2 4/9 of 100cm^2 = 400/9 cm^2 Since we need to find the side of the square we must take the square root of 400 9 \frac{400}{9} = 20 3 \frac{20}{3} cm^2 as our answer.

I will get used to latex soon.

Anbuselvi Me - 1 week, 1 day ago

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Great, so I guess you read our comments?

SRIJAN Singh - 1 week, 1 day ago

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