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Find the digit sum of the sum of all the 10 d i g i t 10-digit numbers that can be formed using { 0 , 1 , 2 , 3 , . . . , 8 , 9 } \{0,1,2,3,...,8,9\} without repetition.

Note : Digit sum of "12345" is 1+2+3+4+5= 15 \boxed{15}


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The answer is 90.

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1 solution

Vishnu Bhagyanath
Jun 13, 2015

Let us think about the combinations in ways of arranging the digits. There would be 9 ! 9! ways to arrange any digit at any given place. Therefore there would be 9 ! 9! of each 1 , 2 , 3...9 1,2,3...9 (Zero doesn't contribute to the final digit sum.)

So the total value at each given place is 9 ! × ( 1 + 2 + 3.... + 8 + 9 ) 9! \times (1+2+3....+8+9 ) , and these can be arranged in any of the 10 places (units to billions place).

So the sum of all the 10-digit numbers would be : 9 ! × 45 × ( 1 + 10 + . . . . + 1000000000 ) 9! \times 45 \times (1+10+....+1000000000) 9 ! × 45 × ( 1111111111 ) 9! \times 45 \times (1111111111) 18143999998185600 18143999998185600 (Yes, I used a calculator for the above step, I don't know if there's an easier way to get to the direct digit sum rather than calculate it )

The digit sum of which is : 90 90

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