The sum of three integer cubes is 42. The middle integer is 12602123297335631.

The problem’s question: {\color{#D61F06}\text{The problem's question:}} What's the largest integer by magnitude of the three integers that are cubed and then the cubes summed to give a final sum of 42

Note: the integers may be replicated and maybe positive, negative or zero.

This is a result discovered while reading. It is not original to me.


The answer is 80435758145817515.

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2 solutions

Aaghaz Mahajan
Sep 7, 2019

I'll just leave This over here.........

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Nice read!!! Thanks!

Aaghaz Mahajan - 1 year, 9 months ago

Total [ { 80538738812075974 , 12602123297335631 , 80435758145817515 } 3 ] 42 \text{Total}\left[\{-80538738812075974,12602123297335631,80435758145817515\}^3\right] \Rightarrow 42 .

Can you show that there isn‘t another solution with 1260... 1260... where the biggest cube is bigger?

Simon Kaib - 1 year, 9 months ago

I can not. Can you? If so, then publish it!

A Former Brilliant Member - 1 year, 9 months ago

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