The Table-Tennis Tournament

I show up to a table-tennis tournament with 9 9 people. I decide to join. Then the tournament starts. The tournament is round robin (you play each other once). The probability that I win any table-tennis game is 1 4 \frac{1}{4} . The probability that after the tournament is over I won at least 1 1 game can be written as m n \frac{m}{n} . Find m + n m+n


The answer is 504605.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Since you are going to play once against every other player, you are going to play 9 games. The probability that you win a game is 1 4 \frac{1}{4} , hence the probability that you lose a game is 1 1 4 = 3 4 . 1-\frac{1}{4}=\frac{3}{4}. To win at least one game during the tournament, the only possible situation that can't happen is you lose all games. The probability that you lose all games is given by P = ( 3 4 ) 9 P=(\frac{3}{4})^{9} , hence our final answer is: P = 1 P = 1 ( 3 4 ) 9 = 242461 262144 P' = 1-P = 1 - (\frac{3}{4})^{9} = \frac{242461}{262144} . m n = 242461 262144 m = 242461 , n = 262144 \frac{m}{n} = \frac{242461}{262144} \longrightarrow m=242461 \, , n=262144 m + n = 504605 \large \boxed{m+n=504605}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...