I show up to a table-tennis tournament with people. I decide to join. Then the tournament starts. The tournament is round robin (you play each other once). The probability that I win any table-tennis game is . The probability that after the tournament is over I won at least game can be written as . Find
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Since you are going to play once against every other player, you are going to play 9 games. The probability that you win a game is 4 1 , hence the probability that you lose a game is 1 − 4 1 = 4 3 . To win at least one game during the tournament, the only possible situation that can't happen is you lose all games. The probability that you lose all games is given by P = ( 4 3 ) 9 , hence our final answer is: P ′ = 1 − P = 1 − ( 4 3 ) 9 = 2 6 2 1 4 4 2 4 2 4 6 1 . n m = 2 6 2 1 4 4 2 4 2 4 6 1 ⟶ m = 2 4 2 4 6 1 , n = 2 6 2 1 4 4 m + n = 5 0 4 6 0 5