The Tale of 3 Little Pigs
Three pigs, named A, B, C, are gathering their gold coins to build their houses against the wolf.
Pig B has 1/7 of A's gold coins more than A.
Pig C has 1/4 of B's gold coins more than B.
Finally, Pig A has 18 gold coins less than C.
If the total coins are shared equally among the 3 pigs, how many coins will each of them get?
The answer is 50.
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1 solution
Let A, B, C be the number of coins belonging to the pigs respectively.
B = (1+1/7)A = (8/7)A
C = (1+1/4)(8/7)A = (5/4)(8/7)A = (10/7)A
C - A = (10/7 - 1)A = (3/7)A = 18
So A = 18(7/3) = 42.
B = 42 + 42/7 = 48
C = 42 + 18 = 60
Thus, (A+B+C)/3 = (42+48+60)/3 = 50.
Each pig will get 50 coins equally.