Determine the smallest positive integer such that:
(1) is divisible by 20,
(2) is a perfect cube, and
(3) is a perfect square.
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By condition (1), we must have n = 2 p 5 q m , where p > 1 and neither 2 nor 5 divides m . By condition (2), p and q must both be divisible by 3, and by condition (3) they must be divisible by 2. Thus the smallest such number is n = 2 6 5 6 = 1 0 0 0 0 0 0 .