The Three Conditions

Determine the smallest positive integer n n such that:

(1) n n is divisible by 20,

(2) n 2 n^{2} is a perfect cube, and

(3) n 3 n^{3} is a perfect square.


The answer is 1000000.

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1 solution

Otto Bretscher
May 3, 2015

By condition (1), we must have n = 2 p 5 q m n=2^p5^qm , where p > 1 p>1 and neither 2 nor 5 divides m m . By condition (2), p p and q q must both be divisible by 3, and by condition (3) they must be divisible by 2. Thus the smallest such number is n = 2 6 5 6 = 1000000 n=2^65^6=\boxed{1000000} .

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