THE TOP OF THE BUILDING.

Algebra Level 1

A thief was climbing on a building. He slips 1 meters for every 5 meters he climbs up. If the building is 53 meters high and he takes 5 seconds to climb 1 meters, Find the total time taken by him to get on the top of the building.

325 seconds 324 seconds 323 seconds 322 seconds

4 solutions

Mahdi Raza
Jun 12, 2020

In 25 seconds, the thief climbs 4 meters. In $12 \times 25 = 300$ seconds he will be able to climb $12 \times 4 = 48$ metres. After another $25$ seconds he will climb $5$ more meters, hence reaching the top.

$\text{Total time } = 300 + 25 = \boxed{325}$

Krishna Garg
Mar 7, 2014

Since he climbs 4 meters in each attempt with climbing 5 meters each attempt, but finally after reaching height of 48 meters,in last attemp he reaches top of 53 meters therefore total time will be 260 + 65 secs =325 secs. ANS

K.K.GARG,INDIA

Santosh Nayan
Mar 7, 2014

Solution is 325 sec

Kkn Rajan
Mar 7, 2014

Solution is 325 sec, [ (53 - 5) --> 48 /4 5 * 5 --> 300 + 5m jump ===> 300 + 5 5 --> 325

THE TOP OF THE BUILDING.

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