The above shows a triangle (in blue) with side lengths 3-4-5, that has both a circumscribed circle (in green) and a circle inscribed (in red) inside of it. Find the ratio of areas between the larger circle versus the smaller circle.
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As 3 2 + 4 2 = 5 2 , the triangle is right-angled. Therefore, by the converse of Thale's theorem, the hypotenuse of the triangle is the diameter of the circle. This gives the radius of the green circle as 2 5 = 2 . 5 .
The area of the triangle is A = 2 3 × 4 = 6 . Also we have that A = s r where r is the radius of the incircle and s is the semiperimeter. This gives r = S A = 2 3 + 4 + 5 6 = 1 .
Therefore, the area of the circumcircle is π × 2 . 5 2 and the incircle has area π × 1 2 . The ratio of their areas is 2 . 5 2