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yes, reals...
( − x 2 ) = − 1 2 x x 2 = x 2
hence the statement is true
x 2 = ( − x ) 2
⟹ x 2 − ( − x ) 2 = 0
Using a 2 − b 2 = ( a − b ) ( a + b )
⟹ ( 2 x ) ( 0 ) = 0 which is true
Hence the given equation is true for all reals.
You started off with that as your assumption (call it A), and then reached an implication (call it B), and then reached another implication (call it C).
You have A → B \righarrow C , and while C is true, that tells us nothing about A .
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x 2 = ( − x ) 2 ⇒ x 2 = ( − x ) 2 ⇒ ∣ x ∣ = ∣ − x ∣ ⇒ d e f i n i t e l y t r u e .
Thus the given equation is true for all reals.