There are two circles of equal radius 1 that are centered at points A and B , respectively, and externally tangent to each other. A tangent D C is drawn to both circles, and a square E F G H fits between the circles such that points G and H lie on the line segment D C .
Find the side length of the square.
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I knew there was a easier solution. Must say nice observation hats off to u +1
Oh that is even not a square hahaha how could it be uncomfortable . Get a cushion below it if it is feeling uncomfortable Hahahahaha
m be the side length of the square
letusing Pythagorean Theorem, we have
1 2 = ( 1 − m ) 2 + ( 1 − 2 m ) 2
after expanding and simplifying, we get
m 2 − 2 . 4 m + 0 . 8
Using the quadratic formula to solve for m , we get
m = 2
m = 0 . 4
Since radius is 1 , m must be lesser than 1 , so m = 0 . 4
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