If an object with density equal to that of water and mass equal to 10 kg, is immersed in water so that it reaches depth 'd' and then is released, then how much will the object rise?
DETAILS Take 'd' = 7m
Give answer in meters
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volume of object = volume of water displaced
density of object = density of water
volume * density of object * g = volume of water displaced * density of water * g
thus the buoyant force is equal to the weight of the object and the object doesn't rise.