The voltmeter reading is...... !
What does the voltmeter read in the figure above?
The answer is 4.
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2 solutions
Discussions for this problem are now closed
@Ahmed Salah -Hi! Could you please tell me what you meant by V(2-3,6,4)=.....?..I actually go the values of the current using Kirchoof's Laws...Please elcuidate...thnx! :)
I m e a n t h e V o f t h e g r o u p c o n s i s t i n g o f 2 Ω a n d 3 Ω , 6 Ω , 4 Ω = t h e V o f t h e b r a n c h c o n s i s t i n g o f 3 Ω , 6 Ω , 4 Ω a s t h e y a r e i n p a r a l l e l . e x c u s e m e f o r m y d e l a y ! !
Calculate equivalent resistance by using series and parallel method. consider resistance of voltmeter is infinite and find out coming current through 12 V battery which is 4 A, distribute in series resistance ((4,8,8),(3,6,4)) and you will get 3 A and 1 A respectively and now you get voltage across 4 ohm resistor is 4 V which is reading of voltmeter.
{ R }_{ 1 }^{ ` }=1.2Ω\\ { R }_{ 2 }^{ ` }={ (\cfrac { 1 }{ 4 } +\cfrac { 1 }{ 8 } +\cfrac { 1 }{ 8 } ) }^{ -1 }=2Ω\\ { R }_{ 3 }^{ ` }={ (\cfrac { 1 }{ 3 } +\frac { 1 }{ 6 } ) }^{ -1 }+\quad 4\quad =6Ω\\ { R }_{ 2 }^{ ` }\quad ,\quad { R }_{ 3 }^{ ` }\quad are\quad in\quad parallel\\ { R }_{ 1 }^{ ` }\quad is\quad respectively\quad \\ \boxed { Now,\quad you\quad yourself\quad should\quad draw\quad \\ the\quad circuit\quad to\quad complete.\\ -leave\quad the\quad voltmeter\quad as\quad it\quad is\quad in\quad \\ parallel\quad with\quad 4Ω-\\ use\quad your\quad mind\quad ,\quad and\quad draw\quad it\quad well } \\ Hence;\\ { R }_{ t }=\cfrac { { R }_{ 2 }^{ ` }\times { R }_{ 3 }^{ ` } }{ { R }_{ 2 }^{ ` }+{ R }_{ 3 }^{ ` } } +{ R }_{ 1 }^{ ` }\\ \quad \quad =\cfrac { 2\times 6 }{ 2+6 } +1.2=2.7Ω\\ { I }_{ t }=\cfrac { { V }_{ B } }{ { R }_{ t }+r } =\cfrac { 12 }{ 2.7+.3 } =4A\\ \\ { V }_{ (2-3,6,4) }={ V }_{ (3,6,4) }\\ { I }_{ t }\times 1.5=I\times 6\\ 4\times 1.5=I\times 6\\ { I }_{ (4) }=\cfrac { 4\times 1.5 }{ 6 } =1A\\ V={ I }_{ (4) }{ R }_{ (4) }\\ \quad =\quad 1\times 4=\boxed { 4V } \\