Thermal equilibrium

Chemistry Level 1

In a thermally isolated tub, we have 600,0 Kg of water at the temperature of 25C°, then a block made of copper of mass 448,0 Kg is added. If the block has an initial temperature of 580C° what is approximately the temperature (in C°) when the thermal equilibrium is reached?

99°C 61°C 75°C 73°C 85°C

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1 solution

Andrea Virgillito
Mar 25, 2017

Q = m c Δ t Q=m*c*\Delta t

Q a c q u i r e d H 2 O Q_{acquired H_{2}O} = - Q g i v e n C u Q_{given Cu}

m H 2 O c H 2 0 Δ t = m C u c C u Δ t m_{H_{2}O}*c_{H_{2}0}*\Delta t =-m_{Cu}*c_{Cu}*\Delta t

Where Δ t = ( t t 0 ) \Delta t = (t-t_{0})

600 , 00 k g 1 , 00 k c a l k g ° C ( t 25 ° C ) = 448 , 00 k g 0 , 093 k c a l k g ° C ( t 580 ° C ) 600,00kg*1,00 \frac{kcal}{kg°C}*(t-25°C)=-448,00kg*0,093 \frac{kcal}{kg°C}*(t-580°C)

t 61 ° C t \simeq 61°C

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