Thermistor Circuit (1)

In the circuit above, if both switch S 1 S_1 and switch S 2 S_2 are open, calculate the voltage difference in volts between node A A and node B B at 2 5 C 25^\circ C ( V A V B V_A-V_B ). (The resistance of the thermistor R T R_T is 1875 Ω 1875\ \Omega at 2 5 C 25^\circ C ).

Try also part 2 and part 3 .


The answer is -7.

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2 solutions

Charley Shi
Nov 12, 2020

Current can only flow through resistors R 1 R_1 through R 4 R_4 since both switches are open. These resistors are in series so current through all of these resistors is I s = 2 mA I_s = 2\textrm{mA} .

The voltage at node A in terms of the voltage at node B: V A = V B I s ( R 2 + R 4 ) V_A = V_B - I_s(R_2+R_4) V A V B = I s ( R 2 + R 4 ) = 2 ( 1.5 + 2 ) V_A - V_B = - I_s(R_2+R_4) = -2(1.5 + 2) = 7 V = \boxed{-7\textrm{V}}

In part 2, did you purposely omit the value of R S R_S ?

Steven Chase - 7 months ago

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There's no R s R_s ?

Charley Shi - 7 months ago

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Ah, so it is R 5 R_5 . Thanks

Steven Chase - 7 months ago

@Charley Feng , I got non-integer answer for part 2. Can you check?

Chew-Seong Cheong - 7 months ago

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My answer is correct.

Charley Shi - 7 months ago
Chew-Seong Cheong
Nov 13, 2020

The voltage difference V A B = ( 1.5 + 2 ) ( 2 ) = 7 V V_{AB} = (1.5+2)(-2) = \boxed{-7} \ \rm V .

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