One ice cube is dropped into of water in a thermally insulated container. If the water is initially at , and the ice comes from directly from a freezer at . What is the final temperature (in celsius) at thermal equilibrium?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Lets consider the whole system to be water at 0 degree celsius.
Heat released by water=MC dT= 200/1000×4190×25=20950
Heat absorbed by ice=MC dT+ML=50/1000×2220×15+333000×50÷1000=1665+16650=18315
So we have a total heat of 20950-18315=2635 for a 250 gm water.
So temperature rise= heat/(MC)=2635/((250/1000)×4190)=2.5155 degree celsius.