Consider the above cycle where the gas is diatomic.
Find the efficiency of the cycle ABCDA.( = η ) .
Now consider the following reaction(Unbalanced)
N X 2 + H X 2 → N H X 3
If the percentage yeild of the above reaction is 8 3 1 0 0 η .
At t = 0 , 2 moles of N X 2 and 8 . 9 moles of H X 2 .
If N moles of N H X 3 is obtained.
Then it is used in the following reaction to get product of [ A g ( N H X 3 ) X 2 ] X + .
The following reaction(unbalanced) was used for preparation of [ A g ( N H X 3 ) X 2 ] X + .
A g X + + N H X 3 → [ A g ( N H X 3 ) X 2 ] X + (Percentage yeild 100%) .
If the volume of container used in preparation of [ A g ( N H X 3 ) X 2 ] X + is 2 L .
Find concentration of [ A g ( N H X 3 ) X 2 ] X + in molarity after end of reaction.
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Ratio of isobaric and isochoric specific heats of a diatomic gas is (7/5). The first law efficiency of the given cycle is (4/31). Thus the reaction yield of the first reaction is 50%. Therefore 2 moles of ammonia is produced in the reaction, and 1 mole of the ion is produced in the container. Since the volume of the container is 2 litres, the required molarity is (1/2) or 0.5