Thermodynamics # 2

1 mole of ammonium chloride vaporizes @ 345K ........ the enthalpy change of the reaction being 1.725 KJ................ what is the Entropy change in this process?? ( in Joule per Kelvin )


The answer is 5.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Chirag Gupta
Jun 5, 2014

delta H=Tdelta s therefor delta H/T=answer I(considring equilibrium G=H-TS DERIVATIVE OF THIS GIBBS LAW EQUATION)

Mayank Holmes
May 29, 2014

entropy change = ( ( change in enthalpy of the reaction )/(absolute temperature) )

why only s,p,d,f block is named in modern periodic why not A B C D or else

Sudhir Yadav - 7 years ago

Log in to reply

Because SPDF are name of subshell and element whose outermost electron enter in spdf orbitol they arepresent in spdf block respectivly Hence.......

vaishnav saykar - 7 years ago

Log in to reply

you r right what u r saying but my question is why it is named as spdf only as these alphabets are so different in sequence ........

Sudhir Yadav - 7 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...