Nested roots, varying powers!

Algebra Level 4

10 100 30 20 10 = x ( x 1 ) ! × x x + 1 \huge \sqrt[10]{\sqrt[20]{\sqrt[30]{{\ddots}_{\sqrt[100]{10}}}}} = \sqrt[(x - 1)! × x^{x + 1}]{x}

Find the real value of x x (upto 2 decimal places) satisfying the real equation above.


This is one part of the set Fun with exponents


The answer is 10.00.

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1 solution

Ashish Menon
May 4, 2016

10 100 30 20 10 = x ( x 1 ) ! × x x + 1 10 1 10 × 1 20 × 1 30 × × 1 100 = x 1 ( x 1 ) ! × x x + 1 10 1 1 × 2 × 3 × × 10 × 1 10 10 = x 1 ( x 1 ) ! × x × x x 10 1 10 ! × 10 10 = x 1 x ! × x x x = 10 \begin{aligned} \huge \sqrt[10]{\sqrt[20]{\sqrt[30]{{\ddots}_{\sqrt[100]{10}}}}} & = \huge \sqrt[(x - 1)! × x^{x + 1}]{x}\\ \\ \Large {10}^{\tfrac{1}{10} × \tfrac{1}{20} × \tfrac{1}{30} × \cdots × \tfrac{1}{100}} & = \Large x^{\tfrac{1}{(x - 1)! × x^{x + 1}}}\\ \\ \Large {10}^{\tfrac{1}{1 × 2 × 3 × \cdots × 10} × \tfrac{1}{{10}^{10}}} & = \Large x^{\tfrac{1}{(x - 1)! × x × x^x}}\\ \\ \Large {10}^{\tfrac{1}{10! × {10}^{10}}} & = \Large x^{\tfrac{1}{x! × x^x}}\\ \\ \Large \therefore x & = \boxed{10} \end{aligned}

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