A geometry problem by Parth Sankhe

Geometry Level pending

There is a circle with centre at ( 2 , 3 ) (2,-3) and radius = 4 4 . There is a point P ( 7 , 1 ) P(7,1) on the exterior of the circle.

Find the equation of the line which bisects the tangents from P P to the circle.

If the line can be expressed in the form a x + b y c = 0 ax+by-c=0 where a,b,c are positive coprime integers, find the value of a + b + c a+b+c .


The answer is 71.

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1 solution

Parth Sankhe
Oct 28, 2018

Assume P to be a point circle and write its equation assuming its radius to be 0. Accordingly, the line asked for becomes the radical axis of the 2 circles. Equate their equations S 1 = 0 S_1=0 and S 2 = 0 S_2=0 to give the radical axis, and thus the answer. L 10 x + 8 y = 53 L\rightarrow 10x+8y=53

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